x^2/(1+x^2-2x)=4,40

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Solution for x^2/(1+x^2-2x)=4,40 equation: 



x^2/(1+x^2-2x)=4.40

We move all terms to the left:

x^2/(1+x^2-2x)-(4.40)=0



Domain of the equation: (1+x^2-2x)!=0

We move all terms containing x to the left, all other terms to the right

x^2-2x!=-1

x∈R



We add all the numbers together, and all the variables

x^2/(1+x^2-2x)-(4.4)=0

We add all the numbers together, and all the variables

x^2/(1+x^2-2x)-4.4=0

We multiply all the terms by the denominator


x^2-(4.4)*(1+x^2-2x)=0

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